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You can also find related Interview Question to A person has certain number of cows and birds.they have 172 eyes and 344 legs.how many cows and birds does he have?  below:

### A person has 14 red socks and 14 white socks in a drawer. What is the minimum number of socks that he should take to get a correct pair?

This is a classic probability puzzle and many puzzles are based on this logic. If the person picks up two socks then there is a possibility of them being different in colour. If he picks up three socks then they are guaranteed red or white. So the minimum number of socks required are three (3).
(More...)

### Minimum number of queues needed to implement the priority queue?

Two. One queue is used for actual storing of data and another for storing priorities. (More...)

### What is Version Number in Assembly Manifest ?

A revision and build number in an assemblies is called Version Number.

There are Major and Minor Version number in an assembly. you can change this version number in assemblyinfo.cs file
usually version number looks like this in assemblyinfo.cs
1.0.*

The common language run time uses these numbers to enforce version policy. (More...)

### How to get IP Number of a SYSTEM?

(or)
Request.UserHostName.ToString(); (More...)

### What is the maximum number of instances supported by SQL Server 2008 Enterprise edition and Standard edition respectively?

50 and 50 (More...)

### How to Find Number of Days for provided date range?

Code extract :

TimeSpan DayDifference = Convert.ToDateTime("2009-1-7").Subtract(Convert.ToDateTime("2009-1-1"));

To find the difference of the days, here we have used Subtract method. The Subtract method does not take start date into consideration. Hence, to get the exact number of days for the date range we need to add one more day to the result.

Response.Write("Number of Days : " + DayDifference.Days+1); (More...)

### What will be the OutPut of the following Query? Select CELING(7.69) as number

OutPut:8 (More...)

### How to get number of Maximum connection can be establish to SQL

select @@MAX_Connections (More...)

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