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Html.BeginForm and Returning Model

Posted By:      Posted Date: August 31, 2010    Points: 0   Category :ASP.Net
Any idea how can View return model(myModelValues) on the click of submit button,aspx code     <% Html.BeginForm("submit", "RenewalManager", FormMethod.Post); %>    <input type="submit" name="submitButton" onclick=" return confirmReject()" value="Test" />    <% Html.EndForm ( ); %> controller code        public ActionResult submit(string submitButton)        {            switch (submitButton)            {  //Cases...                case "Test":                    // call another action to perform the cancellation                     return (Confirm());  //...             }        }        public ActionResult Test()        {  

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Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. 

Exception Details: System.Argu

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