.NET Tutorials, Forums, Interview Questions And Answers
Welcome :Guest
Sign In
Register
 
Win Surprise Gifts!!!
Congratulations!!!


Top 5 Contributors of the Month
david stephan
Asad Ali
Fauzul Azmi
Post New Web Links

How to enable datasheedt view?

Posted By:      Posted Date: October 12, 2010    Points: 0   Category :SharePoint
 

When try to display datasheet view on a list, i get an error message.

What should be configured and is there any known issue with 64-bit operating system on my PC?


keren tsur


View Complete Post


More Related Resource Links

Enable view in List toolbar

  
Hey guys, I accidentially deleted the webpart for the Product List. When I added it back in, it doesn't show the Views to filter the content for. I.e.  "My Projects",  "Closed Projects", "Open Projects", etc...

The views are created, I can't figure out how to show them in that dropdownlist on the toolbar that allows to create new or edit.

Please help... =(


Also, how do I edit the Project List form? I want to add more fields to it.

Truly Understanding View State

  
This article provides a detailed understanding of the ViewState.

GridView Parent Child View with JQuery Effects

  
I was just checked how to add some more cool effects to the GridView control using JQuery. In this post I will display parent-child data in the GridView control with some help of the wonderful JQuery library.

Let's first populate the GridView control.

How Do I Enable Inline GridView Editing?

  
Now that you have created a site with Edit and Details views, how do you enable inline editing in a GridView control? This video shows you how, and also touches on routing.

Model View Controller (MVC) for ASP.NET

  
Model View Controller (MVC) architectures, immediately wonder how the MVC pattern can be applied in an ASP.NET world. This article will demonstrate how the MVC pattern can be applied to an ASP.NET web application and still maintain the basic Microsoft supplied architecture.

jQuery grid view plugin

  
jqGridView is new, client-rich, XML-based, ajax grid plugin for jQuery library. jqGridView provides professional solution for representing and editing tabular data on the web. Carefully designed, with powerful script API, this editable DHTML grid is easy configurable with XML, and shows convincing results working with large amounts of data. jqGridView allows easy implementation of nice looking(managed through css). jqGridView is not platform-depending plug-in, it can be used with different web -programming platforms like: ASP .NET/ASP, PHP, JAVA, CGI scripts etc. jqGridView has hight bowser compatibility.

jQuery grid view plugin

  
jqGridView is new, client-rich, XML-based, ajax grid plugin for jQuery library. jqGridView provides professional solution for representing and editing tabular data on the web. Carefully designed, with powerful script API, this editable DHTML grid is easy configurable with XML, and shows convincing results working with large amounts of data. jqGridView allows easy implementation of nice looking(managed through css

view state vs request parameters

  

If  the view state is the data entered into the form fields then they are supposed to be available in the request parameters or request body. Then why would we need view state for?


Thanks.



Form view in ASP.NET

  

hi all...!
i have a database and i create a form with button edit,delete, New Registration..using Formview in asp.net..
everything was working good...

And i write SQL statement to get New ID number into dropdownlist/TextBox when i click button "New Registration".

i can get new(next) ID number after read database
it's also working good

Now i want change it to get ID which was deleted from table and replace the ID with new record...what i need is when i click "New Registration" i want get deleted "ID" first and then go to new record ID...

my code is here:-it working for get next ID after read database.

SELECT min(PANG)
FROM (SELECT ID + 1 AS PANG
FROM Table1
EXCEPT SELECT ID FROM Table1)
AS boon WHERE PANG >300000
</p>

Gridview Enable Selection Problem

  

Hi,


I have a gridview with Enable selection and Enable Paging equals to TRUE.

I also set the PageSize of my gridview to 4 so that I only displays 4 rows per page.

The problem is when I click the pager in the bottom of my gridview, my gridview is disappearing and no records appear.


Here is code behind of my gridview:

If e.Row.RowType = DataControlRowType.DataRow Then
                e.Row.Attributes("style") = "cursor:pointer"

                e.Row.Cells(2).Attributes.Add("onclick", Page.ClientScript.GetPostBackEventReference(sender, "Select$" & e.Row.RowIndex.ToString))
                e.Row.Cells(3).Attributes.Add("onclick", Page.ClientScript.GetPostBackEventReference(sender, "Select$" & e.Row.RowIndex.ToString))
                e.Row.Cells(4).Attributes.Add("onclick", Page.ClientScript.GetPostBackEventReference(sender, "Select$" & e.Row.RowIndex.ToString))
                e.Row.Cells(5).Attributes.Add("onclick", Page.ClientScript.GetPostBackEventReference(sender, "Select$" & e.Row.RowIndex.ToString))
                e.Row.Cells(6).Attributes.Add("onclick", Page.ClientScript.GetPostBackEventReference(sender, "Select$" & e.Row.RowIndex.ToString))
   

partial view, 2 controllers

  

 Hi,

This is my first visit to the forums, I hope someone here can help me

 

I'm writing a small webapplication for creating repair tickets and adding comments, really basic

now I'm writing this in MVC2

So I have 2 controllers, 1 HomeController that does everything related to the tickets (listing tickets, creating new ones, editing) and 1 controller for the comments

the edit view for the homecontroller contains a partial view for /comment/create

so /home/edit/ticketnumber can edit the title and status of the ticket on the left side of the screen, the right side of the screen contains the partial view for adding comments

this is done like this:

Html.Renderaction("Create", "Comment");


but if I look at the generated html code when running the app, both save buttons go to /home/edit/ticketnumber

so the comment is never saved.

 

I hope this makes sense and that someone can help me solve this


WebDev.WebServer.exe has encounted a problem and needs to close when trying to view page in browser

  

Hi, whenever I load an aspx page in vwde2008, I get the message in the subject of this post.  After I click Ok on that, I get a dialog box, Unable to Connect to the ASP.Net development center.  What can I do to troubleshoot?

I am using Windows XP SP3, vwde2008 with SP1, on a HP desktop.  Also using Office 2003 if that is relevant at all.

Thanks, Justin


View State Encryption

  

Hi All,

Why is it that I see the same hash value generated when I use different algorithms for viewstate encryption. I have added below lines to the web.config file

<pages viewstateEncryptionMode="Always"

Custom Control Design view error

  

Hi

I have created a custom control from scratch and it works fine as in you can build the project that uses it and it works fine at runtime. Problem is when you go to design view the control shows an error in the place of where the control should be rendered.

Error: '<SomeValue>' Could not be set to '<SomeProperty>'


This shows up on all my custom set properties. These properties are created as basic as possible. I can give the properties values in Source view and run the app just fine. I can even add a Onclick event. If I don't set any custom properties the control will render fine in Design view. It's only when I set a value to a custom property.


Property Code Example:

public string Text
        {
            get
            {
                string ret = "";
                object obj = ViewState["Text"];
                if (obj != null)
                {
                    ret = obj.ToString();
                }
                return ret;
            }
            set
            {
                ViewState["Text"] = value;
            }
        }


I've even removed the Category and Description tags with no difference.

I don't know if what I said makes sens, but I hope it

ReportViewer :: Failed to enable constraints. But my statement is valid!!

  
  • A
  • n error has occurred during report processing.
      • Exception has been thrown by the target of an invocation.
        • Failed to enable constraints. One or more rows contain values violating non-null, unique, or foreign-key constraints.

    Why do I keep getting this error, even when not using any data on the report. When I run the query in SQL server I get a resultset. However when I try to render the report I get this error.

    Thanks!


    Crystal Report Asking for Database Authentication each time when I view Page.

      

    Whenever I open my Crystal Report page, I am taken to the Database Authentication page where I am asked for

    User name
    Data Name
    Password

    each time.

    Is there a way to avoid this and I save these authentication in my page once.

    I am using VS2005, C#.

    Any Help will be appriciated.

    Thanks
    Asif


    Design Patterns: Problems and Solutions with Model-View-ViewModel

      

    The Model-View-ViewModel (MVVM) design pattern describes a popular approach for building Windows Presentation Foundation or Microsoft Silverlight applications. Robert McCarter shows you how the ViewModel works, and discuss some benefits and issues involved in implementing a ViewModel in your code.

    Robert McCarter

    MSDN Magazine July 2010


    Categories: 
    ASP.NetWindows Application  .NET Framework  C#  VB.Net  ADO.Net  
    Sql Server  SharePoint  Silverlight  Others  All   

    Hall of Fame    Twitter   Terms of Service    Privacy Policy    Contact Us    Archives   Tell A Friend