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Send model back when form post

Posted By:      Posted Date: October 10, 2010    Points: 0   Category :ASP.Net

public ActionResult DisplayView1()


  EmployeeModel myModel = new EmployeeModel();


  return View(myModel);


When I hit the sumit button on the view, that's method of the view is "post". How do I pass the original model back to the action?

<form id="employeeForm" name=employeeForm" action=<%Model.ActionName %> method="post">

<%Model.ActionName %> will be in this example equals "PostBackFromView"

I would like to have this:


public ActionResult PostBackFromView(EmployeeModel model)



What should I do in the view to enable the pass back of the model?


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