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Display xml file records in a gridview

Posted By:satyapriyanayak       Posted Date: July 02, 2013    Points: 40    Category: ASP.NET Controls    URL: http://www.dotnetspark.com  

Display xml file records in a gridview

Here we will know how to display xml file records in a gridview. We can also insert selected records to the database by selecting the checkbox.

<%@ Page Language="C#" AutoEventWireup="true"  CodeFile="Default.aspx.cs" Inherits="_Default" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title>Untitled Page</title>
    <form id="form1" runat="server">
    <asp:GridView ID="GridView1" runat="server" Width="96%"   >
            <asp:TemplateField HeaderText="Select">
                    <asp:CheckBox ID="chkbox" runat="server"></asp:CheckBox>
                        <asp:TemplateField HeaderText="Remark">
                  <asp:Label ID="lblremark" runat="server"></asp:Label>
    <asp:Button ID="btnview" runat="server" onclick="btnview_Click" 
        Text="Show Records " />
    <asp:FileUpload ID="FileUpload1" runat="server" />
    <asp:Button ID="btninsert" runat="server" onclick="btninsert_Click" 
        Text="Insert Records" /><br />
    <asp:Label ID="Label1" runat="server" Text="Label"></asp:Label>

using System;
using System.Configuration;
using System.Data;
using System.Linq;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.HtmlControls;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Xml.Linq;
using System.Data.SqlClient;
public partial class _Default : System.Web.UI.Page
    string connStr = ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString;
    string filename;
    string str;
    protected void Page_Load(object sender, EventArgs e)

    protected void btnview_Click(object sender, EventArgs e)

        SqlConnection con = new SqlConnection(connStr);

        GridView1.Visible = true;
        DataSet reportData = new DataSet();
        filename = System.IO.Path.GetExtension(FileUpload1.FileName.ToString());
        if (filename == ".xml")
            GridView1.DataSource = reportData;
            GridView1.Visible = false;
            Response.Write("Invalid File");
    protected void btninsert_Click(object sender, EventArgs e)
        SqlConnection con = new SqlConnection(connStr);
        for (int i = 0; i < GridView1.Rows.Count; i++)
            GridViewRow row = GridView1.Rows[i];

            CheckBox chkbox = (CheckBox)row.FindControl("chkbox");

            if (chkbox.Checked == true)
                str = "insert into employee (empid,empname,empaddress,empcity,empstate,empzip,emplic,empstatus,empp,empi) values('" + row.Cells[2].Text + "','" + row.Cells[3].Text + "','" + row.Cells[4].Text + "','" + row.Cells[5].Text + "','" + row.Cells[6].Text + "','" + row.Cells[7].Text + "','" + row.Cells[8].Text + "','" + row.Cells[9].Text + "','" + row.Cells[10].Text + "','" + row.Cells[11].Text + "')";
                SqlCommand com=new SqlCommand(str,con);

            Label1.Text = "Records inserted";



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