Retrieve Path of a File Using OpenFileDialog

OpenFileDialog fd = new OpenFileDialog();

string NameOfFile = "";
string path = "";

if (fd.ShowDialog() == DialogResult.OK)
{
  NameOfFile = System.IO.Path.GetFileName(fd.FileName);
  path = System.IO.Path.GetDirectoryName(fd.FileName);
}

MessageBox.Show(NameOfFile, "Name Of File");
MessageBox.Show(path, "Directory");